The forum pages are fully operational! See this link for the latest forum topics, where users can collaborate or discuss certain topics in one place!

Difference between revisions of "Vance Legstrong"

From Arthur Wiki
Jump to navigationJump to search
(→‎top: add cat)
Tag: apiedit
Line 1: Line 1:
{{Youmay|Vance Legstrong, a cyclist who appeared in [[Binky vs. Binky]]|[[Lance Armstrong]]}}{{Character infobox
{{Youmay|Vance Legstrong, a cyclist who appeared in [[Binky vs. Binky]]|[[Lance Armstrong]]}}
{{Character infobox
|image = Vance Legstrong.png
|image = Vance Legstrong.png
|gender = Male
|gender = Male
Line 6: Line 7:
|complexion = Cream
|complexion = Cream
|cartoon first appeared = "[[Binky vs. Binky]]"
|cartoon first appeared = "[[Binky vs. Binky]]"
|cartoon last appeared = "[[D.W.'s Stray Netkitten]]" <small>(cameo)</small>}}'''Vance Legstrong '''is a cyclist who taught [[Binky Barnes|Binky]] to race against himself. He is a parody of famous cyclist [[Lance Armstrong]].
|cartoon last appeared = "[[D.W.'s Stray Netkitten]]" <small>(cameo)</small>}}
 
'''Vance Legstrong '''is a cyclist who taught [[Binky Barnes|Binky]] to race against himself. He is a parody of famous cyclist [[Lance Armstrong]].
{{Clr}}{{Stub}}


{{Clr}}
{{Stub}}
[[Category:Bears]]
[[Category:Bears]]
[[Category:Minor characters]]
[[Category:Characters]]
[[Category:Characters]]
[[Category:Male]]
[[Category:Male]]
Line 19: Line 20:
[[Category:Pages needing attention]]
[[Category:Pages needing attention]]
[[Category:A to Z]]
[[Category:A to Z]]
[[Category:Secondary Characters]]

Revision as of 08:46, 23 August 2018

This article is about Vance Legstrong, a cyclist who appeared in Binky vs. Binky. You may be looking for Lance Armstrong.
Vance Legstrong
Vance Legstrong.png
Gender Male
Animal Bear

Hair color Brown
Complexion Cream

Vance Legstrong is a cyclist who taught Binky to race against himself. He is a parody of famous cyclist Lance Armstrong.

802-23.PNG I will take care of this!

This article or section is a stub. You can help Arthur Wiki by expanding it